1CGELSD(1)             LAPACK driver routine (version 3.2)            CGELSD(1)
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NAME

6       CGELSD  -  computes  the  minimum-norm  solution to a real linear least
7       squares problem
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SYNOPSIS

10       SUBROUTINE CGELSD( M, N, NRHS, A, LDA, B, LDB, S,  RCOND,  RANK,  WORK,
11                          LWORK, RWORK, IWORK, INFO )
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13           INTEGER        INFO, LDA, LDB, LWORK, M, N, NRHS, RANK
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15           REAL           RCOND
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17           INTEGER        IWORK( * )
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19           REAL           RWORK( * ), S( * )
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21           COMPLEX        A( LDA, * ), B( LDB, * ), WORK( * )
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PURPOSE

24       CGELSD  computes  the  minimum-norm  solution  to  a  real linear least
25       squares problem:
26           minimize 2-norm(| b - A*x |)
27       using the singular value decomposition (SVD)  of  A.  A  is  an  M-by-N
28       matrix which may be rank-deficient.
29       Several right hand side vectors b and solution vectors x can be handled
30       in a single call; they are stored as the columns of the M-by-NRHS right
31       hand side matrix B and the N-by-NRHS solution matrix X.
32       The problem is solved in three steps:
33       (1) Reduce the coefficient matrix A to bidiagonal form with
34           Householder tranformations, reducing the original problem
35           into a "bidiagonal least squares problem" (BLS)
36       (2) Solve the BLS using a divide and conquer approach.
37       (3) Apply back all the Householder tranformations to solve
38           the original least squares problem.
39       The  effective rank of A is determined by treating as zero those singu‐
40       lar values which are less than RCOND times the largest singular value.
41       The divide and conquer algorithm  makes  very  mild  assumptions  about
42       floating  point arithmetic. It will work on machines with a guard digit
43       in add/subtract, or on those binary machines without guard digits which
44       subtract  like the Cray X-MP, Cray Y-MP, Cray C-90, or Cray-2. It could
45       conceivably fail on hexadecimal or decimal machines without guard  dig‐
46       its, but we know of none.
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ARGUMENTS

49       M       (input) INTEGER
50               The number of rows of the matrix A. M >= 0.
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52       N       (input) INTEGER
53               The number of columns of the matrix A. N >= 0.
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55       NRHS    (input) INTEGER
56               The  number of right hand sides, i.e., the number of columns of
57               the matrices B and X. NRHS >= 0.
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59       A       (input/output) COMPLEX array, dimension (LDA,N)
60               On entry, the M-by-N matrix A.  On exit, A has been destroyed.
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62       LDA     (input) INTEGER
63               The leading dimension of the array A. LDA >= max(1,M).
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65       B       (input/output) COMPLEX array, dimension (LDB,NRHS)
66               On entry, the M-by-NRHS right hand side matrix B.  On  exit,  B
67               is  overwritten  by the N-by-NRHS solution matrix X.  If m >= n
68               and RANK = n, the residual sum-of-squares for the  solution  in
69               the  i-th  column is given by the sum of squares of the modulus
70               of elements n+1:m in that column.
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72       LDB     (input) INTEGER
73               The leading dimension of the array B.  LDB >= max(1,M,N).
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75       S       (output) REAL array, dimension (min(M,N))
76               The singular values of A in decreasing  order.   The  condition
77               number of A in the 2-norm = S(1)/S(min(m,n)).
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79       RCOND   (input) REAL
80               RCOND  is  used to determine the effective rank of A.  Singular
81               values S(i) <= RCOND*S(1) are treated as zero.  If RCOND  <  0,
82               machine precision is used instead.
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84       RANK    (output) INTEGER
85               The  effective  rank  of A, i.e., the number of singular values
86               which are greater than RCOND*S(1).
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88       WORK    (workspace/output) COMPLEX array, dimension (MAX(1,LWORK))
89               On exit, if INFO = 0, WORK(1) returns the optimal LWORK.
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91       LWORK   (input) INTEGER
92               The dimension of the array WORK. LWORK must be at least 1.  The
93               exact  minimum  amount  of workspace needed depends on M, N and
94               NRHS. As long as LWORK is at least 2 * N + N *  NRHS  if  M  is
95               greater  than  or  equal  to N or 2 * M + M * NRHS if M is less
96               than N, the code will execute correctly.  For good performance,
97               LWORK  should  generally  be  larger.   If  LWORK  = -1, then a
98               workspace query is assumed; the  routine  only  calculates  the
99               optimal  size  of  the  array WORK and the minimum sizes of the
100               arrays RWORK and IWORK, and returns these values as  the  first
101               entries  of the WORK, RWORK and IWORK arrays, and no error mes‐
102               sage related to LWORK is issued by XERBLA.
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104       RWORK   (workspace) REAL array, dimension (MAX(1,LRWORK))
105               LRWORK >= 10*N + 2*N*SMLSIZ + 8*N*NLVL + 3*SMLSIZ*NRHS +  (SML‐
106               SIZ+1)**2 if M is greater than or equal to N or 10*M + 2*M*SML‐
107               SIZ + 8*M*NLVL + 3*SMLSIZ*NRHS + (SMLSIZ+1)**2  if  M  is  less
108               than N, the code will execute correctly.  SMLSIZ is returned by
109               ILAENV and is equal to the maximum size of the  subproblems  at
110               the bottom of the computation tree (usually about 25), and NLVL
111               = MAX( 0, INT( LOG_2( MIN( M,N )/(SMLSIZ+1) ) ) + 1 ) On  exit,
112               if INFO = 0, RWORK(1) returns the minimum LRWORK.
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114       IWORK   (workspace) INTEGER array, dimension (MAX(1,LIWORK))
115               LIWORK  >=  max(1, 3*MINMN*NLVL + 11*MINMN), where MINMN = MIN(
116               M,N ).  On exit, if INFO =  0,  IWORK(1)  returns  the  minimum
117               LIWORK.
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119       INFO    (output) INTEGER
120               = 0: successful exit
121               < 0: if INFO = -i, the i-th argument had an illegal value.
122               >  0:   the algorithm for computing the SVD failed to converge;
123               if INFO = i, i off-diagonal elements of an intermediate bidiag‐
124               onal form did not converge to zero.
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FURTHER DETAILS

127       Based on contributions by
128          Ming Gu and Ren-Cang Li, Computer Science Division, University of
129            California at Berkeley, USA
130          Osni Marques, LBNL/NERSC, USA
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134 LAPACK driver routine (version 3.N2o)vember 2008                       CGELSD(1)
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