1/*************************************************
2* PCRE DEMONSTRATION PROGRAM *
3*************************************************/
4
5/* This is a demonstration program to illustrate the most straightforward ways
6of calling the PCRE regular expression library from a C program. See the
7pcresample documentation for a short discussion ("man pcresample" if you have
8the PCRE man pages installed).
9
10In Unix‐like environments, if PCRE is installed in your standard system
11libraries, you should be able to compile this program using this command:
12
13gcc ‐Wall pcredemo.c ‐lpcre ‐o pcredemo
14
15If PCRE is not installed in a standard place, it is likely to be installed with
16support for the pkg‐config mechanism. If you have pkg‐config, you can compile
17this program using this command:
18
19gcc ‐Wall pcredemo.c ‘pkg‐config ‐‐cflags ‐‐libs libpcre‘ ‐o pcredemo
20
21If you do not have pkg‐config, you may have to use this:
22
23gcc ‐Wall pcredemo.c ‐I/usr/local/include ‐L/usr/local/lib \
24 ‐R/usr/local/lib ‐lpcre ‐o pcredemo
25
26Replace "/usr/local/include" and "/usr/local/lib" with wherever the include and
27library files for PCRE are installed on your system. Only some operating
28systems (e.g. Solaris) use the ‐R option.
29
30Building under Windows:
31
32If you want to statically link this program against a non‐dll .a file, you must
33define PCRE_STATIC before including pcre.h, otherwise the pcre_malloc() and
34pcre_free() exported functions will be declared __declspec(dllimport), with
35unwanted results. So in this environment, uncomment the following line. */
36
37/* #define PCRE_STATIC */
38
39#include <stdio.h>
40#include <string.h>
41#include <pcre.h>
42
43#define OVECCOUNT 30 /* should be a multiple of 3 */
44
45
46int main(int argc, char **argv)
47{
48pcre *re;
49const char *error;
50char *pattern;
51char *subject;
52unsigned char *name_table;
53unsigned int option_bits;
54int erroffset;
55int find_all;
56int crlf_is_newline;
57int namecount;
58int name_entry_size;
59int ovector[OVECCOUNT];
60int subject_length;
61int rc, i;
62int utf8;
63
64
65/**************************************************************************
66* First, sort out the command line. There is only one possible option at *
67* the moment, "‐g" to request repeated matching to find all occurrences, *
68* like Perl’s /g option. We set the variable find_all to a non‐zero value *
69* if the ‐g option is present. Apart from that, there must be exactly two *
70* arguments. *
71**************************************************************************/
72
73find_all = 0;
74for (i = 1; i < argc; i++)
75 {
76 if (strcmp(argv[i], "‐g") == 0) find_all = 1;
77 else break;
78 }
79
80/* After the options, we require exactly two arguments, which are the pattern,
81and the subject string. */
82
83if (argc ‐ i != 2)
84 {
85 printf("Two arguments required: a regex and a subject string\n");
86 return 1;
87 }
88
89pattern = argv[i];
90subject = argv[i+1];
91subject_length = (int)strlen(subject);
92
93
94/*************************************************************************
95* Now we are going to compile the regular expression pattern, and handle *
96* and errors that are detected. *
97*************************************************************************/
98
99re = pcre_compile(
100 pattern, /* the pattern */
101 0, /* default options */
102 &error, /* for error message */
103 &erroffset, /* for error offset */
104 NULL); /* use default character tables */
105
106/* Compilation failed: print the error message and exit */
107
108if (re == NULL)
109 {
110 printf("PCRE compilation failed at offset %d: %s\n", erroffset, error);
111 return 1;
112 }
113
114
115/*************************************************************************
116* If the compilation succeeded, we call PCRE again, in order to do a *
117* pattern match against the subject string. This does just ONE match. If *
118* further matching is needed, it will be done below. *
119*************************************************************************/
120
121rc = pcre_exec(
122 re, /* the compiled pattern */
123 NULL, /* no extra data ‐ we didn’t study the pattern */
124 subject, /* the subject string */
125 subject_length, /* the length of the subject */
126 0, /* start at offset 0 in the subject */
127 0, /* default options */
128 ovector, /* output vector for substring information */
129 OVECCOUNT); /* number of elements in the output vector */
130
131/* Matching failed: handle error cases */
132
133if (rc < 0)
134 {
135 switch(rc)
136 {
137 case PCRE_ERROR_NOMATCH: printf("No match\n"); break;
138 /*
139 Handle other special cases if you like
140 */
141 default: printf("Matching error %d\n", rc); break;
142 }
143 pcre_free(re); /* Release memory used for the compiled pattern */
144 return 1;
145 }
146
147/* Match succeeded */
148
149printf("\nMatch succeeded at offset %d\n", ovector[0]);
150
151
152/*************************************************************************
153* We have found the first match within the subject string. If the output *
154* vector wasn’t big enough, say so. Then output any substrings that were *
155* captured. *
156*************************************************************************/
157
158/* The output vector wasn’t big enough */
159
160if (rc == 0)
161 {
162 rc = OVECCOUNT/3;
163 printf("ovector only has room for %d captured substrings\n", rc ‐ 1);
164 }
165
166/* Show substrings stored in the output vector by number. Obviously, in a real
167application you might want to do things other than print them. */
168
169for (i = 0; i < rc; i++)
170 {
171 char *substring_start = subject + ovector[2*i];
172 int substring_length = ovector[2*i+1] ‐ ovector[2*i];
173 printf("%2d: %.*s\n", i, substring_length, substring_start);
174 }
175
176
177/**************************************************************************
178* That concludes the basic part of this demonstration program. We have *
179* compiled a pattern, and performed a single match. The code that follows *
180* shows first how to access named substrings, and then how to code for *
181* repeated matches on the same subject. *
182**************************************************************************/
183
184/* See if there are any named substrings, and if so, show them by name. First
185we have to extract the count of named parentheses from the pattern. */
186
187(void)pcre_fullinfo(
188 re, /* the compiled pattern */
189 NULL, /* no extra data ‐ we didn’t study the pattern */
190 PCRE_INFO_NAMECOUNT, /* number of named substrings */
191 &namecount); /* where to put the answer */
192
193if (namecount <= 0) printf("No named substrings\n"); else
194 {
195 unsigned char *tabptr;
196 printf("Named substrings\n");
197
198 /* Before we can access the substrings, we must extract the table for
199 translating names to numbers, and the size of each entry in the table. */
200
201 (void)pcre_fullinfo(
202 re, /* the compiled pattern */
203 NULL, /* no extra data ‐ we didn’t study the pattern */
204 PCRE_INFO_NAMETABLE, /* address of the table */
205 &name_table); /* where to put the answer */
206
207 (void)pcre_fullinfo(
208 re, /* the compiled pattern */
209 NULL, /* no extra data ‐ we didn’t study the pattern */
210 PCRE_INFO_NAMEENTRYSIZE, /* size of each entry in the table */
211 &name_entry_size); /* where to put the answer */
212
213 /* Now we can scan the table and, for each entry, print the number, the name,
214 and the substring itself. */
215
216 tabptr = name_table;
217 for (i = 0; i < namecount; i++)
218 {
219 int n = (tabptr[0] << 8) | tabptr[1];
220 printf("(%d) %*s: %.*s\n", n, name_entry_size ‐ 3, tabptr + 2,
221 ovector[2*n+1] ‐ ovector[2*n], subject + ovector[2*n]);
222 tabptr += name_entry_size;
223 }
224 }
225
226
227/*************************************************************************
228* If the "‐g" option was given on the command line, we want to continue *
229* to search for additional matches in the subject string, in a similar *
230* way to the /g option in Perl. This turns out to be trickier than you *
231* might think because of the possibility of matching an empty string. *
232* What happens is as follows: *
233* *
234* If the previous match was NOT for an empty string, we can just start *
235* the next match at the end of the previous one. *
236* *
237* If the previous match WAS for an empty string, we can’t do that, as it *
238* would lead to an infinite loop. Instead, a special call of pcre_exec() *
239* is made with the PCRE_NOTEMPTY_ATSTART and PCRE_ANCHORED flags set. *
240* The first of these tells PCRE that an empty string at the start of the *
241* subject is not a valid match; other possibilities must be tried. The *
242* second flag restricts PCRE to one match attempt at the initial string *
243* position. If this match succeeds, an alternative to the empty string *
244* match has been found, and we can print it and proceed round the loop, *
245* advancing by the length of whatever was found. If this match does not *
246* succeed, we still stay in the loop, advancing by just one character. *
247* In UTF‐8 mode, which can be set by (*UTF8) in the pattern, this may be *
248* more than one byte. *
249* *
250* However, there is a complication concerned with newlines. When the *
251* newline convention is such that CRLF is a valid newline, we must *
252* advance by two characters rather than one. The newline convention can *
253* be set in the regex by (*CR), etc.; if not, we must find the default. *
254*************************************************************************/
255
256if (!find_all) /* Check for ‐g */
257 {
258 pcre_free(re); /* Release the memory used for the compiled pattern */
259 return 0; /* Finish unless ‐g was given */
260 }
261
262/* Before running the loop, check for UTF‐8 and whether CRLF is a valid newline
263sequence. First, find the options with which the regex was compiled; extract
264the UTF‐8 state, and mask off all but the newline options. */
265
266(void)pcre_fullinfo(re, NULL, PCRE_INFO_OPTIONS, &option_bits);
267utf8 = option_bits & PCRE_UTF8;
268option_bits &= PCRE_NEWLINE_CR|PCRE_NEWLINE_LF|PCRE_NEWLINE_CRLF|
269 PCRE_NEWLINE_ANY|PCRE_NEWLINE_ANYCRLF;
270
271/* If no newline options were set, find the default newline convention from the
272build configuration. */
273
274if (option_bits == 0)
275 {
276 int d;
277 (void)pcre_config(PCRE_CONFIG_NEWLINE, &d);
278 /* Note that these values are always the ASCII ones, even in
279 EBCDIC environments. CR = 13, NL = 10. */
280 option_bits = (d == 13)? PCRE_NEWLINE_CR :
281 (d == 10)? PCRE_NEWLINE_LF :
282 (d == (13<<8 | 10))? PCRE_NEWLINE_CRLF :
283 (d == ‐2)? PCRE_NEWLINE_ANYCRLF :
284 (d == ‐1)? PCRE_NEWLINE_ANY : 0;
285 }
286
287/* See if CRLF is a valid newline sequence. */
288
289crlf_is_newline =
290 option_bits == PCRE_NEWLINE_ANY ||
291 option_bits == PCRE_NEWLINE_CRLF ||
292 option_bits == PCRE_NEWLINE_ANYCRLF;
293
294/* Loop for second and subsequent matches */
295
296for (;;)
297 {
298 int options = 0; /* Normally no options */
299 int start_offset = ovector[1]; /* Start at end of previous match */
300
301 /* If the previous match was for an empty string, we are finished if we are
302 at the end of the subject. Otherwise, arrange to run another match at the
303 same point to see if a non‐empty match can be found. */
304
305 if (ovector[0] == ovector[1])
306 {
307 if (ovector[0] == subject_length) break;
308 options = PCRE_NOTEMPTY_ATSTART | PCRE_ANCHORED;
309 }
310
311 /* Run the next matching operation */
312
313 rc = pcre_exec(
314 re, /* the compiled pattern */
315 NULL, /* no extra data ‐ we didn’t study the pattern */
316 subject, /* the subject string */
317 subject_length, /* the length of the subject */
318 start_offset, /* starting offset in the subject */
319 options, /* options */
320 ovector, /* output vector for substring information */
321 OVECCOUNT); /* number of elements in the output vector */
322
323 /* This time, a result of NOMATCH isn’t an error. If the value in "options"
324 is zero, it just means we have found all possible matches, so the loop ends.
325 Otherwise, it means we have failed to find a non‐empty‐string match at a
326 point where there was a previous empty‐string match. In this case, we do what
327 Perl does: advance the matching position by one character, and continue. We
328 do this by setting the "end of previous match" offset, because that is picked
329 up at the top of the loop as the point at which to start again.
330
331 There are two complications: (a) When CRLF is a valid newline sequence, and
332 the current position is just before it, advance by an extra byte. (b)
333 Otherwise we must ensure that we skip an entire UTF‐8 character if we are in
334 UTF‐8 mode. */
335
336 if (rc == PCRE_ERROR_NOMATCH)
337 {
338 if (options == 0) break; /* All matches found */
339 ovector[1] = start_offset + 1; /* Advance one byte */
340 if (crlf_is_newline && /* If CRLF is newline & */
341 start_offset < subject_length ‐ 1 && /* we are at CRLF, */
342 subject[start_offset] == ’\r’ &&
343 subject[start_offset + 1] == ’\n’)
344 ovector[1] += 1; /* Advance by one more. */
345 else if (utf8) /* Otherwise, ensure we */
346 { /* advance a whole UTF‐8 */
347 while (ovector[1] < subject_length) /* character. */
348 {
349 if ((subject[ovector[1]] & 0xc0) != 0x80) break;
350 ovector[1] += 1;
351 }
352 }
353 continue; /* Go round the loop again */
354 }
355
356 /* Other matching errors are not recoverable. */
357
358 if (rc < 0)
359 {
360 printf("Matching error %d\n", rc);
361 pcre_free(re); /* Release memory used for the compiled pattern */
362 return 1;
363 }
364
365 /* Match succeeded */
366
367 printf("\nMatch succeeded again at offset %d\n", ovector[0]);
368
369 /* The match succeeded, but the output vector wasn’t big enough. */
370
371 if (rc == 0)
372 {
373 rc = OVECCOUNT/3;
374 printf("ovector only has room for %d captured substrings\n", rc ‐ 1);
375 }
376
377 /* As before, show substrings stored in the output vector by number, and then
378 also any named substrings. */
379
380 for (i = 0; i < rc; i++)
381 {
382 char *substring_start = subject + ovector[2*i];
383 int substring_length = ovector[2*i+1] ‐ ovector[2*i];
384 printf("%2d: %.*s\n", i, substring_length, substring_start);
385 }
386
387 if (namecount <= 0) printf("No named substrings\n"); else
388 {
389 unsigned char *tabptr = name_table;
390 printf("Named substrings\n");
391 for (i = 0; i < namecount; i++)
392 {
393 int n = (tabptr[0] << 8) | tabptr[1];
394 printf("(%d) %*s: %.*s\n", n, name_entry_size ‐ 3, tabptr + 2,
395 ovector[2*n+1] ‐ ovector[2*n], subject + ovector[2*n]);
396 tabptr += name_entry_size;
397 }
398 }
399 } /* End of loop to find second and subsequent matches */
400
401printf("\n");
402pcre_free(re); /* Release memory used for the compiled pattern */
403return 0;
404}
405
406/* End of pcredemo.c */
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